
- A

- B

- C

- ✓








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take place in two steps :
$(a)$ $Br^{-} + H^{+} + H_2O_2 \xrightarrow{{slow}} HOBr + H_2O$
$(b)$ $HOBr + Br^{-} + H^{+} \xrightarrow{{fast}} H_2O + Br_2$
The order of the reaction is
$\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{CH \equiv C - C - OH}
\end{array}}\limits_{\rm{I}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_2} = CH - C - OH}
\end{array}}\limits_{{\rm{II}}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_3} - C{H_2} - C - OH}
\end{array}}\limits_{{\rm{III}}} $$\mathop {\begin{array}{*{20}{c}}
\,\,\,{C{H_3}\,\,\,\,\,\,O}\\
\,\,\,{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_3} - CH - C - OH}
\end{array}}\limits_{{\rm{IV}}} $
