Question
Making use of the cube root table, find the cube root $1346$
✓
Answer
By prime factorisation, we have:$1346 = 2 \times 673$
$\Rightarrow\sqrt[3]{1346}$ $=\sqrt[3]{2}\times\sqrt[3]{673}$ Also $670 < 673 < 680$
$\Rightarrow\sqrt[3]{670}<\sqrt[3]{673}<\sqrt[3]{680}$ For the difference $(680 - 670)$, i.e., $10$,
the difference in the values $= 8.794 - 8.750 = 0.044$
$\therefore$ For the difference of $(673 - 670),$ i.e., $3$,
the difference in the values $=\frac{0.004}{10}\times3= 0.013$ (upto three decimal places)
$\therefore\sqrt[3]{673}$ $=8.750 +0.013$ $=8.763$ Now $\sqrt[3]{1346}$
$=\sqrt[3]{2}\times=\sqrt[3]{673}$ $=1.260\times8.763$
$=11.041$ (Up to three decimal places) Thus, the answer is $11.041$.
$\Rightarrow\sqrt[3]{1346}$ $=\sqrt[3]{2}\times\sqrt[3]{673}$ Also $670 < 673 < 680$
$\Rightarrow\sqrt[3]{670}<\sqrt[3]{673}<\sqrt[3]{680}$ For the difference $(680 - 670)$, i.e., $10$,
the difference in the values $= 8.794 - 8.750 = 0.044$
$\therefore$ For the difference of $(673 - 670),$ i.e., $3$,
the difference in the values $=\frac{0.004}{10}\times3= 0.013$ (upto three decimal places)
$\therefore\sqrt[3]{673}$ $=8.750 +0.013$ $=8.763$ Now $\sqrt[3]{1346}$
$=\sqrt[3]{2}\times=\sqrt[3]{673}$ $=1.260\times8.763$
$=11.041$ (Up to three decimal places) Thus, the answer is $11.041$.
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Represent the following data by a pie-diagram:
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Items of expenditure
|
Expenditure
|
|
|
Family $A$
|
Family $B$
|
|
|
Food
|
$4000$
|
$6400$
|
|
Clothing
|
$2500$
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$480$
|
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Rent
|
$1500$
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$3200$
|
|
Education
|
$400$
|
$1000$
|
|
Miscellaneous
|
$1600$
|
$600$
|
|
Total
|
$10000$
|
$16000$
|