Question
Making use of the cube root table, find the cube root $5112$
✓
Answer
By prime factorisation, we have:
$5112=2^3 \times 3^2 \times 71$
$\Rightarrow\sqrt[3]{5112}$
$=2\times\sqrt[3]{9}\times\sqrt[3]{71}$
By the cube root table, we have:
$\sqrt[3]{9}=2.080$ and $\sqrt[3]{71}=4.141$
$\therefore\sqrt[3]{5112}$
$=2\times\sqrt[3]{9}\times\sqrt[3]{71}$
$=2\times2.080\times4.141$
$=17.227$ (upto three decimal places)
Thus, the required cube root is $17.227.$
$5112=2^3 \times 3^2 \times 71$
$\Rightarrow\sqrt[3]{5112}$
$=2\times\sqrt[3]{9}\times\sqrt[3]{71}$
By the cube root table, we have:
$\sqrt[3]{9}=2.080$ and $\sqrt[3]{71}=4.141$
$\therefore\sqrt[3]{5112}$
$=2\times\sqrt[3]{9}\times\sqrt[3]{71}$
$=2\times2.080\times4.141$
$=17.227$ (upto three decimal places)
Thus, the required cube root is $17.227.$
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