Question
Making use of the cube root table, find the cube root $732$
✓
Answer
We have: $730 < 732 < 740$ $\Rightarrow\sqrt[3]{730}<\sqrt[3]{732}<\sqrt[3]{740}$
From cube root table, we have: $\sqrt[3]{730}=9.004 $ and $\sqrt[3]{740}=9.045$
For the difference $(740 -730)$, i.e., $10$, the difference in values $= 9.045 - 9.004 = 0.041$
$\therefore$ For the difference of $(732 - 730),$ i.e.,$ 2,$ the difference in the values $= 0.0082$
$\therefore\sqrt[3]{732}$
$=9.004 +0.008$
$=9.012$
From cube root table, we have: $\sqrt[3]{730}=9.004 $ and $\sqrt[3]{740}=9.045$
For the difference $(740 -730)$, i.e., $10$, the difference in values $= 9.045 - 9.004 = 0.041$
$\therefore$ For the difference of $(732 - 730),$ i.e.,$ 2,$ the difference in the values $= 0.0082$
$\therefore\sqrt[3]{732}$
$=9.004 +0.008$
$=9.012$
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