Question
Making use of the cube root table, find the cube root 732

Answer

We have:
730 < 732 < 740
$\Rightarrow\sqrt[3]{730}<\sqrt[3]{732}<\sqrt[3]{740}$
From cube root table, we have:
$\sqrt[3]{730}=9.004 $ and $\sqrt[3]{740}=9.045$
For the difference (740 -730), i.e., 10, the difference in values
= 9.045 - 9.004 = 0.041
$\therefore$ For the difference of (732 - 730), i.e., 2, the difference in the values
$= 0.0082$
$\therefore\sqrt[3]{732}$
$=9.004 +0.008$
$=9.012$

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