Question
Making use of the cube root table, find the cube root $7342$
✓
Answer
We have:
From cube root table, we have:
$7300 < 7342 < 7400$
$\Rightarrow\sqrt[3]{7000}<\sqrt[3]{7342}<\sqrt[3]{7400}$
From the cube root table, we have:
$\sqrt[3]{7300}=19.39 $ and $\sqrt[3]{7400}=19.48$
$\therefore$ For the difference of $(7400 - 7300)$, i.e., $100$, the difference in the values
$= 19.48 - 19 - 39 = 0.09$
$\therefore$ For the difference of $(7342 - 7300)$, i.e., $42$, the difference in the values
$=\frac{0.09}{100}\times42= 0.0378$
$= 0.037$
$\therefore\sqrt[3]{7342}$
$=19.39 +0.037$
$=19.427$
From cube root table, we have:
$7300 < 7342 < 7400$
$\Rightarrow\sqrt[3]{7000}<\sqrt[3]{7342}<\sqrt[3]{7400}$
From the cube root table, we have:
$\sqrt[3]{7300}=19.39 $ and $\sqrt[3]{7400}=19.48$
$\therefore$ For the difference of $(7400 - 7300)$, i.e., $100$, the difference in the values
$= 19.48 - 19 - 39 = 0.09$
$\therefore$ For the difference of $(7342 - 7300)$, i.e., $42$, the difference in the values
$=\frac{0.09}{100}\times42= 0.0378$
$= 0.037$
$\therefore\sqrt[3]{7342}$
$=19.39 +0.037$
$=19.427$
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