Question
Making use of the cube root table, find the cube root 9800

Answer

We have:
9800 = 98 × 100
$\therefore \sqrt[3]{9800}$
$=\sqrt[3]{98\times100}$
$=\sqrt[3]{98}\times\sqrt[3]{100}$
By cube root table, we have:
$\sqrt[3]{98}=4.610 $ and $\sqrt[3]{100}=4.642 $
$\therefore\sqrt[3]{9800}$
$=\sqrt[3]{98}\times\sqrt[3]{100}$
$= 4.610 \times4.642=21.40$ (upto three decimal places)
Thus, the required cube root is 21.40.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free