MCQ
Manganese achieves its highest oxidation state in its compound
- A$Mn{O_3}$
- B$M{n_3}{O_4}$
- ✓$KMn{O_4}$
- D${K_2}Mn{O_4}$
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$NH_4HS(s) \rightleftharpoons NH_3 (g) + H_2S(g)$
If more $NH_4HS$ is added to the equilibrium
${C_6}{H_5}(l)\, + \,\frac{{15}}{2}\,{O_2}(g)\, \to \,6\,C{O_2}(g)\, + \,3{H_2}O\,(l);$ $\Delta H = \,-\,3271\,kJ$
What is $\Delta U$ for the combustion of $1.5\,mole$ of benzene at $27\,^oC$ ? .....$kJ$

$MnO_4^ - + 5F{e^{2 + }} + 8{H^ + } \to M{n^{2 + }} + 5F{e^{3 + }} + 4{H_2}O$,
here $10\, ml$ of $0.1\, M$ $KMn{O_4}$ is equivalent to
$\begin{array}{*{20}{c}} {N \equiv C} \\ {N \equiv C}\end{array}\,\,\left. {} \right\rangle C = C\,\left\langle {} \right.\,\begin{array}{*{20}{c}} {C \equiv N} \\ {C \equiv N} \end{array}$