MCQ
Mark against the correct answer in the following: Two complementary angles differ by $10^\circ $. The larger angle is:
- ✓$60^\circ$
- B$50^\circ$
- C$64^\circ$
- D$54^\circ$
Let first angle $= x$
Then second $= 90^\circ - x$
$x - (90^\circ - x) = 10$
$\Rightarrow x - 90^\circ + x = 10^\circ $
$\Rightarrow 2x = 10^\circ + 90^\circ = 100^\circ $
$x = 50^\circ $
Second angle $= 90^\circ - 50^\circ = 40^\circ $
Larger angle $= 50^\circ $
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