MCQ
Mark $(\checkmark)$ against the correct answer in the following:
$\frac{-102}{119}$ in standard form is:
$\frac{-102}{119}$ in standard form is:
- A$\frac{-4}{7}$
- ✓$\frac{-6}{7}$
- C$\frac{-6}{17}$
- DNone of these.
✓
Answer
Correct option: B.
$\frac{-6}{7}$
$H.C.F$ of $102 $and $119$ is $17$
$=\frac{-102\div11}{119\div17}=\frac{-6}{7}$
The standard from of $\frac{-102}{119}\text{ is }\frac{-6}{7}$
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