MCQ
Mark $(\checkmark)$ against the correct answer in the following:
$\Big(\frac{-3}{4}\Big)^{-3}=?$
  • A
    $\frac{27}{64}$
  • B
    $\frac{64}{27}$
  • C
    $\frac{-27}{64}$
  • $\frac{-64}{27}$

Answer

Correct option: D.
$\frac{-64}{27}$

$\Big(\frac{-3}{4}\Big)^{-3}=\Big(\frac{4}{-3}\Big)^3$ $\Big[\text{Since}\Big(\frac{\text{a}}{\text{b}}\Big)^{-\text{n}}=\Big(\frac{\text{b}}{\text{a}}\Big)^\text{n}\Big]$
$=\frac{4^3}{(-3)^3}$
$=\frac{4\times4\times4}{(-3)\times(-3)\times(-3)}=\frac{64}{(-27)}$
$=\frac{64\times-1}{-27\times-1}=\frac{-64}{27}$

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