Mark ( ) against the correct answer in the following: What should… - Vidyadip

MCQ

Mark $(\checkmark)$ against the correct answer in the following:
What should be subtracted from $\frac{-3}{4}$ to get $\frac{5}{6}?$

A
$\frac{19}{12}$
✓
$\frac{-19}{12}$
C
$\frac{1}{12}$
D
$\frac{-1}{12}$

✓

Answer

Correct option: B.

$\frac{-19}{12}$

The correct option is $(b).$
Let the number that is to be subtracted be $x.$
$\frac{-3}{4}-\text{x}=\frac{5}{6}$
$\Rightarrow-\text{x}=\frac{5}{6}-\Big(\frac{-3}{4}\Big)$
$\Rightarrow-\text{x}=\frac{5}{6}+\frac{-3}{4}$
$\Rightarrow-\text{x}=\frac{(5\times2)+(3\times3)}{12}$
$\Rightarrow\text{x}=-\frac{19}{12}$
Hence, $\frac{-19}{12}$ should be subtracted from $\frac{-3}{4}$ to get $\frac{5}{6}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q. [1 Marks Each]" from Rational Numbers→Rational Numbers — all question types→MATHS STD 7 question papers→Gujarat Board STD 7 question papers→Gujarat Board question paper generator→

Similar questions

Which of the following is not zero?

$1.02 \div 6=?$

The mean of first six multiples of 5 is

Mark $(\checkmark)$ against the correct answer.In the given figure, $AOB$ is a straight line, $\angle\text{AOC}=\text{(3x-8)}^\circ$, $\angle\text{COD}=50^\circ$ and $\angle\text{BOD}=\text{(x+10)}^\circ$. The value of $x$ is:

Mark against the correct answer in the following: If $4.5\ m$ of a uniform rod weighs $17.1\ kg,$ what is the weight of $12\ m$ of such a rod$?$

The angles of a triangle are in the ratio 2: 3: 7. The measure of the largest angle is

The area of a semicircle of radius $4r$ is:

In Fig. $, A O B$ is a straight line such that $\angle A O C=(3 x+10)^{\circ}, \angle C O D=50^{\circ}$ and $\angle B O D=(x-8)^{\circ}$ The value of $x$ is

→

The length of a rectangle $8\ cm$ more than the breadth. If the perimeter of the rectangle is $80\ cm$, then the area of the rectangle is:

A triangle has altitudes: