MCQ
Mark $(\checkmark)$ against the correct answer.In the given figure, $\text{AOB}$ is a straight line, $\angle\text{AOC}=\text{(3x-8)}^\circ$, $\angle\text{COD}=50^\circ$ and $\angle\text{BOD}=\text{(x+10)}^\circ$. The value of $x$ is:
  • $32$
  • B
    $42$
  • C
    $36$
  • D
    $52$

Answer

Correct option: A.
$32$

$\text{AOB}$ is a straight line
$\angle\text{AOC}+\angle\text{COD+}\angle\text{DOB}=180^\circ$
$\Rightarrow 3x - 8^\circ + 50^\circ + x + 10^\circ = 180^\circ $
$\Rightarrow 4x = 180^\circ + 8^\circ - 50^\circ - 10^\circ $
$\Rightarrow 4x = 128^\circ $
$\Rightarrow x = 32^\circ $

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