MCQ
Mark $(\checkmark)$ against the correct answer: In $\triangle\text{ABC,}$ side $BC$ has been produced to $D$ such that $\angle\text{ADC}=125^\circ$ and $\angle\text{BAC}=60^\circ$ Then $\angle\text{ABC}={}?$:
  • A
    $55^\circ $
  • B
    $60^\circ$
  • $65^\circ $
  • D
    $70^\circ $

Answer

Correct option: C.
$65^\circ $
$\angle\text{ACD}=125^\circ$
$\angle\text{ACD}=\angle\text{CAB}+\angle\text{ABC}$
($\because$ the exterior angles are equal to the sum of its interior opposite angles)
$\therefore\angle\text{ABC}=125^\circ-60^\circ=65^\circ$

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