MCQ
Mark $(\checkmark)$ against the correct answer.In $\triangle\text{ABC},$ side $BC$ has been produced to $D$. If $\angle\text{BAC}=45^\circ$ and $\angle\text{ABC}=55^\circ$ then $\angle\text{ACD}={ ?}$
  • A
    $80^\circ$
  • B
    $90^\circ$
  • $100^\circ$
  • D
    $110^\circ$

Answer

Correct option: C.
$100^\circ$

In $\triangle\text{ABC,}$ side $BC$ is produced to $D$
$\angle\text{A}=45^\circ, \angle\text{B}=55^\circ,$
Ext. $\angle\text{ACD}=\angle\text{A}+\angle\text{B}$
$45^\circ+55^\circ=100^\circ$

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