MCQ
Mark $(\checkmark)$ against the correct answer:
$\triangle\text{ABC},$ is an isosceles right triangle in which $\angle\text{A}=90^\circ$ and BC = 6cm. Then AB = ?
  • A
    $2\sqrt{2}\text{cm}$
  • $3\sqrt{2}\text{cm}$
  • C
    $4\sqrt{2}\text{cm}$
  • D
    $2\sqrt{3}\text{cm}$

Answer

Correct option: B.
$3\sqrt{2}\text{cm}$
$3\sqrt{2}\text{cm}$

Here, $A B=A C$

In right angled isoceles triangle:

$BC^2=AB^2+AC^2$

$\Rightarrow BC^2=2 AB^2$

$\Rightarrow 36=2 AB^2$

$\Rightarrow AB{ }^2=\frac{36}{2}$

$\Rightarrow AB=\sqrt{18}$

$\Rightarrow AB=3 \sqrt{2} cm$

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