MCQ
Mark $(\checkmark)$ against the correct answer. $\triangle\text{ABC}$ is an isosceles triangle with $\angle\text{C}=90^\circ$ and $AC = 5\ cm.$ then, $AB = ?$
- A$2.5\ cm.$
- B$5 \ cm.$
- C$15\ m.$
- ✓$5\sqrt2\text{cm.}$
✓
Answer
Correct option: D.
$5\sqrt2\text{cm.}$
$\triangle \mathrm{ABC}$ is an isosceles triangle
$\angle \mathrm{C}=90^{\circ}$
$\mathrm{AC}=5 \mathrm{~cm}$
$\mathrm{BC}=\mathrm{AC}=5 \mathrm{~cm}$
$\text { In right } \triangle \mathrm{ABC}$
$\mathrm{AB}^2=\mathrm{AC}^2+\mathrm{BC}^2=(5)^2+(5)^2=25+25=50=2 \times 25$
$\mathrm{AB}=\sqrt{2 \times 25}=5 \sqrt{2} \mathrm{~cm}$
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