MCQ
Mark $(\checkmark)$ tick against the correct answer in the following:
$\Bigg[\bigg\{\Big(-\frac{1}{2}\Big)^2\bigg\}^{-2}\Bigg]^{-1}=?$
  • $\frac{1}{16}$
  • B
    $16$
  • C
    $\frac{-1}{16}$
  • D
    $-16$

Answer

Correct option: A.
$\frac{1}{16}$

$\Bigg[\bigg\{\Big(-\frac{1}{2}\Big)^2\bigg\}^{-2}\Bigg]^{-1}=\Big(\frac{-1}{2}\Big)^{2\times(-2)\times(-1)}$
$=\Big(\frac{-1}{2}\Big)^4=\Big(\frac{-1}{2}\Big)\Big(\frac{-1}{2}\Big)\Big(\frac{-1}{2}\Big)\Big(\frac{-1}{2}\Big)$
$=\frac{1}{16}$

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