Mark the wrong statement: - Vidyadip

MCQ

Mark the wrong statement:

✓
The primal and dual have equal number of variables.
B
The shadow price indicates the change in the value of the objective function, per unit increase in the value of the RHS.
C
The shadow price of a non$-$binding constraint is always equal to zero.
D
The information about shadow price of a constraint is important since it may be possible to purchase or, otherwise, acquire additional units of the concerned resource.

✓

Answer

Correct option: A.

The primal and dual have equal number of variables.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Programming→Linear Programming — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

If the points $A (-1,3,2), B (-4,2,-2)$ and $C (5,5, \lambda)$ are collinear then the value of $\lambda$ is

$\int_{}^{} {{{\sin }^2}x\cos x\;dx} $ is equal to

Let $f$ and $g$ are twice differentiable functions such that $f(x).g(x) = 1\,\, \forall x \in R$ and $f'$ and $g'$ are never zero, then $\frac{{f^{''}(x)}}{{f(x)}} + \frac{{g^{''}(x)}}{{g(x)}}$ equals-

Let $M$ and $m$ be respectively the local maximum and the local minimum values of the function, $f(x) = \,2{x^3} - 9{x^2} + 12x + 5$ in the interval $[0, 3].$ Then $M-m$ is equal to

A box contain $100$ pens of which $10$ are defective. What is the probability that out of a sample of $5$ pens draws one by one with replacement at most one is defective?

Let $f(x) = \left\{ \begin{array}{l}{x^p}\sin \frac{1}{x},x \ne 0\\0\,\,\,\,\,\,\,\,\,\,\,\,\,\,,x = 0\end{array} \right.$ then $f(x)$ is continuous but not differential at $x = 0$ if

The solution of the differential equation $x\,dy - y\,dx = (\sqrt {{x^2} + {y^2})} dx$is

Choose the correct answer in Exercise:
If $\text{f (a}+\text{b)}-\text{x}=\text{f (x)},$ then $\int^{\text{b}}_{\text{a}}\text{x f (x)}\ \text{dx}$ is equal to

Consider $f(x)=\left\{\begin{matrix}
tan^{-1}(\frac{\alpha x+\beta}{\gamma})\ \ \ x\in(0,\frac{1}{2}) and \\0 \ \ \ \ \ \ \ x=\frac{1}{2}
and \\ ln(\beta x^2 +2) \ \ \ \ \ \ x\in(\frac{1}{2},1)
and\end{matrix}\right.$ . If $f(x)$ continuous and derivable in its domain then the value of $\alpha + \beta + \gamma$ is-

Let $\text{f(x)}=\frac{\alpha\text{x}}{\text{x}+1},\ \text{x}\neq-1.$ Then, for what value of $\alpha$ is f(f(x)) = x?