Match List I with List II and select the correct answer using the… - Vidyadip

MCQ

Match List $I$ with List $II$ and select the correct answer using the codes given below the lists :

List $I$ (Position of the object)	List $II$ (Magnification)
$(I)$ An object is placed at focus before a convex mirror	$(A)$ Magnification is $-\infty$
$(II)$ An object is placed at centre of curvature before a concave mirror	$(B)$ Magnification is $0.5$
$(III)$ An object is placed at focus before a concave mirror	$(C)$ Magnification is $+1$
$(IV)$ An object is placed at centre of curvature before a convex mirror	$(D)$ Magnification is $-1$
	$(E)$ Magnification is $0.33$

✓
$I-B, II-D, III-A, IV-E$
B
$I-A, II-D, III-C, IV-B$
C
$I-C, II-B, III-A, IV-E$
D
$I-B, II-E, III-D, IV-C$

✓

Answer

Correct option: A.

$I-B, II-D, III-A, IV-E$

a
(a) $\mathrm{m}=\frac{f}{f-u}$

$(A)$ Convex mirror $\mathrm{u}=$ -ve $, \mathrm{f}=+$ ve

$m=\frac{f}{f-(f)}=\frac{1}{2}$

$(B)$ Concave $\rightarrow m=\frac{-f}{-f-(-f)}=\infty$

$(C)$ Concave mirror $\mathrm{u}=-\mathrm{R}(2 \mathrm{f})$

$m=\frac{-f}{-f-(-2 f)}=\frac{-f}{f}=-1$

$(D)$ Convex mirror $\mathrm{u}=-2 \mathrm{f}$

$m=\frac{f}{f-(-2 f)}=\frac{f}{3 f}=\frac{1}{3}$

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