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9. Ray optics abd optical instruments — Physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 SciencePhysics9. Ray optics abd optical instruments1 Mark
MCQ
Match List $I$ with List $II$ and select the correct answer using the codes given below the lists :

List $I$

(Position of the object)

List $II$

(Magnification)

$(I)$ An object is placed at focus before a convex mirror

$(A)$ Magnification is $-\infty$  

$(II)$ An object is placed at centre of curvature before a concave mirror

$(B)$ Magnification is $0.5$

$(III)$ An object is placed at focus before a concave mirror

$(C)$ Magnification is $+1$

$(IV)$ An object is placed at centre of curvature before a convex mirror

$(D)$ Magnification is $-1$

 

$(E)$ Magnification is $0.33$
  • ✓
    $I-B, II-D, III-A, IV-E$
  • B
    $I-A, II-D, III-C, IV-B$
  • C
    $I-C, II-B, III-A, IV-E$
  • D
    $I-B, II-E, III-D, IV-C$
✓

Answer

Correct option: A.
$I-B, II-D, III-A, IV-E$
a
(a) $\mathrm{m}=\frac{f}{f-u}$

$(A)$ Convex mirror $\mathrm{u}=$ -ve $, \mathrm{f}=+$ ve

$m=\frac{f}{f-(f)}=\frac{1}{2}$

$(B)$ Concave $\rightarrow m=\frac{-f}{-f-(-f)}=\infty$

$(C)$ Concave mirror $\mathrm{u}=-\mathrm{R}(2 \mathrm{f})$

$m=\frac{-f}{-f-(-2 f)}=\frac{-f}{f}=-1$

$(D)$ Convex mirror $\mathrm{u}=-2 \mathrm{f}$

$m=\frac{f}{f-(-2 f)}=\frac{f}{3 f}=\frac{1}{3}$

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