STD 12 - 4. Moving charges and magnetism — JEE STD 11 Science — Question

$B _{ ab }=\frac{\mu_0}{4 \pi} \frac{ I }{ r } \text { (out of the plane) }$

$B _{ bcd }=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(2 \pi) \text { (in the plane) }$

$B _{ de }=\frac{\mu_0}{4 \pi} \frac{ I }{ r } \text { (out of the plane) }$

Hence magnetic field at $O$ is

$B _0=-\frac{\mu_0}{4 \pi} \frac{ I }{ r }+\frac{\mu_0}{4 \pi} \frac{ I }{ r }(2 \pi)-\frac{\mu_0}{4 \pi} \frac{ I }{ r }$

$B _0=\frac{\mu_0}{2 \pi} \frac{ I }{ r }(\pi-1) \ldots \ldots . . \text { (III) }$

(B)

$B _{ ab }=\frac{\mu_0}{4 \pi} \frac{ I }{ r } \text { (out of the plane) }$

$B _{ bcd }=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(\pi) \text { (out of the plane) }$

$B _{ de }=\frac{\mu_0}{4 \pi} \frac{ I }{ r } \text { (out of the plane) }$

Hence magnetic field at $O$ is

$B _0=\frac{\mu_0}{4 \pi} \frac{ I }{ r }+\frac{\mu_0}{4 \pi} \frac{ I }{ r }(\pi)+\frac{\mu_0}{4 \pi} \frac{ I }{ r }$

$B _0=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(\pi+2) \ldots .( I )$

(C)

$B _{ ab }=\frac{\mu_0}{4 \pi} \frac{ I }{ r } \text { (in the plane) }$

$B _{ bcd }=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(\pi) \text { (in the plane) }$

$B _{ de }=0 \text { (at the axis) }$

Hence magnetic field at $O$ is

$B _0=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(1+\pi) \ldots(IV)$

$B _{ ab }=0 \text { (at the axis) }$

$B _{ bcd }=\frac{\mu_0}{4 \pi} \frac{ I }{ r }(\pi) \text { (out of the plane) }$

$B _{ de }=0 \text { (at the axis) }$

Hence magnetic field at $O$ is

$B _0=\frac{\mu_0 I }{4 r } \ldots \text { (II) }$