MCQ
$\mathop {\lim }\limits_{n\, \to \,\infty } \frac{{1 - {n^2}}}{{\sum n}} = . . . $
- ✓$-2$
- B$-1$
- C$2$
- D$1$
$ = \mathop {\lim }\limits_{n \to \infty } \,\frac{{2\,(1 - n)}}{n}$
$ = \mathop {\lim }\limits_{n \to \infty } 2\,\left( {\frac{1}{n} - 1} \right)$$ = 2(0 - 1) = - 2$.
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