MCQ
$\mathop {\lim }\limits_{n \to \infty } \frac{{n{{(2n + 1)}^2}}}{{(n + 2)({n^2} + 3n - 1)}} = $
- A$0$
- B$2$
- ✓$4$
- D$\infty $
$ = \mathop {\lim }\limits_{n \to \infty } \frac{{{n^3}\,\left( {4 + \frac{4}{n} + \frac{1}{{{n^2}}}} \right)}}{{{n^3}\left( {1 + \frac{5}{n} + \frac{5}{{{n^2}}} - \frac{2}{{{n^3}}}} \right)}} = 4$
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(where $S = p[{p^4} - 5{p^2}q + 5{q^2}],\;P = {p^2}{q^2}$$({p^4} - 5{p^2}q + 4{q^2})$