_ x 0 (1 - ax)^ 1 x = - Vidyadip

MCQ

$\mathop {\lim }\limits_{x \to 0} {(1 - ax)^{\frac{1}{x}}} = $

A
$e$
✓
${e^{ - a}}$
C
$1$
D
${e^a}$

✓

Answer

Correct option: B.

${e^{ - a}}$

b
(b) $\mathop {\lim }\limits_{x \to 0} \,{[1 + ( - a)\,x]^{1/x}} = {e^{ - a}}$.

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