_ x 0 1 - 6x x = - Vidyadip

MCQ

$\mathop {\lim }\limits_{x \to 0} \frac{{1 - \cos 6x}}{x} = $

✓
$0$
B
$6$
C
$\frac{1}{3}$
D
None of these

✓

Answer

Correct option: A.

$0$

a
$(a)$ $\mathop {\lim }\limits_{x \to 0} \,\frac{{1 - \cos \,\,6x}}{x} = \mathop {\lim }\limits_{x \to 0} \,\frac{{2\,\,{{\sin }^2}3x}}{x} $

$= \mathop {\lim }\limits_{x \to 0} \,\frac{{x\,.\,2\,\,{{\sin }^2}3x}}{{{x^2}}} = 0$.

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