MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{5\sin x + x\cos x}}{{2\tan x - {x^2}}}$ is
  • A
    $\frac{5}{2}$
  • $3$
  • C
    $0$
  • D
    does not exist

Answer

Correct option: B.
$3$
b
$\mathop {\lim }\limits_{x \to 0} \frac{{5\sin x + x\cos x}}{{2\tan x - {x^2}}}$

$\mathop {\lim }\limits_{x \to 0} \frac{{5\frac{{\sin x}}{x} + \cos x}}{{\frac{{2\tan x}}{x} - x}} = \frac{{5 + 1}}{{2 - 0}} = 3$

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