MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{{a^{\sin x}} - 1}}{{{b^{\sin x}} - 1}} = $
- A$\frac{a}{b}$
- B$\frac{b}{a}$
- ✓$\frac{{\log a}}{{\log b}}$
- D$\frac{{\log b}}{{\log a}}$
$ = {\log _e}a \times \frac{1}{{{{\log }_e}b}} = \frac{{\log a}}{{\log b}}$.
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