MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{\int_0^x {\cos {t^2}} }}{x}\,dt = . . .$
- A$0$
- ✓$1$
- C$ - 1$
- Dએકપણ નહી.
Applying $ L- $ Hospital rule, we get
$\mathop {\lim }\limits_{x \to 0} \frac{{\int_0^x {\cos {t^2}dt} }}{x} = \mathop {\lim }\limits_{x \to 0} \frac{{\cos {x^2}}}{1} = 1$.
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