MCQ
$\mathop {\lim }\limits_{x \to 0} \,\frac{{{{\sin }^2}\,x}}{{\sqrt 2 - \sqrt {1 + \cos \,x} }}$ equals
- A$\sqrt 2 $
- ✓$4\sqrt 2 $
- C$4$
- D$2\sqrt 2 $
$ = \frac{{{{\left( 1 \right)}^2}.\left( {2\sqrt 2 } \right)}}{{\frac{1}{2}}} = 4\sqrt 2 $
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