MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{\sqrt {\frac{1}{2}(1 - \cos 2x)} }}{x} = $
- A$1$
- B$-1$
- C$0$
- ✓એકપણ નહી.
So, $\mathop {\lim }\limits_{x \to 0 + } \,\frac{{|\,\sin x\,|}}{x} = 1$ and $\mathop {\lim }\limits_{x \to 0 - } \,\frac{{|\,\sin x\,|}}{x} = - 1$
Hence limit does not exist.
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કારણ $(R)$ : રેખાઓના ઢાળનો ગુણાકાર $= -1$