MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{\tan 2x - x}}{{3x - \sin x}} = $
- A$0$
- B$1$
- ✓$1/2$
- D$1/3$
Aliter : Apply $L-$ Hospital‘s rule
$\mathop {\lim }\limits_{x \to 0} \,\,\frac{{\tan 2x - x}}{{3x - \sin x}} = \mathop {\lim }\limits_{x \to 0} \,\frac{{2{{\sec }^2}2x - 1}}{{3 - \cos x}} = \frac{{2 - 1}}{{3 - 1}} = \frac{1}{2}.$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.