- A$\sin a$
- B$\cos a$
- ✓$ - \sin a$
- D$\frac{1}{2}\cos a$
$ = - 2\,\sin a\,.\,\frac{{(1 - \cos x)}}{{{x^2}}}\,.\,\left( {\frac{x}{{\sin x}}} \right)$
$ = \mathop {\lim }\limits_{x \to 0} \,\, - 2\sin a\,.\,\frac{{2\,{{\sin }^2}(x/2)}}{{4\,{{\left( {\frac{x}{2}} \right)}^2}\,\left( {\frac{{\sin x}}{x}} \right)}} = - \sin a$.
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$STATEMENT -1$ : The ratio $PR$: $RQ$ equals $2 \sqrt{2}: \sqrt{5}$. because
$STATEMENT -2$ : In any triangle, bisector of an angle divides the triangle into two similar triangles.
$(A)$ The length of the line segment $O A_1$ is $4 \sqrt{3}$
$(B)$ The length of the line segment $A_1 B_1$ is 16
$(C)$ The orthocenter of the triangle $A_1 B_1 C_1$ is $(0,0)$
$(D)$ The orthocenter of the triangle $A_1 B_1 C_1$ is $(1,0)$