MCQ
$\mathop {\lim }\limits_{x \to 0} {\left\{ {\tan \left( {\frac{\pi }{4} + x} \right)} \right\}^{1/x}} = $
- A$1$
- B$-1$
- ✓${e^2}$
- D$e$
$ = \mathop {\lim }\limits_{x \to 0} \,\,\frac{{{{\{ {{(1 + \tan x)}^{1/\tan x}}\} }^{(\tan x)/x}}}}{{{{\{ {{(1 - \tan x)}^{1/\tan x}}\} }^{(\tan x)/x}}}} = \frac{e}{{{e^{ - 1}}}} = {e^2}$.
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