MCQ
$\mathop {\lim }\limits_{x \to 1} \frac{{1 + \cos \pi \,x}}{{{{\tan }^2}\pi \,x}}$ is equal to
- A$0$
- ✓$1/2$
- C$1$
- D$2$
[Using $ L-$ Hospital’s rule]
$ = \mathop {\lim }\limits_{x \to 1} \frac{{ - 1}}{2}{\cos ^3}\pi \,x$$ = \frac{1}{2}$.
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