MCQ
$\mathop {\lim }\limits_{x \to a} \frac{{\sqrt {3x - a} - \sqrt {x + a} }}{{x - a}} = $
  • A
    $\sqrt 2 a$
  • $1/\sqrt {2a} $
  • C
    $2a$
  • D
    $1/2a$

Answer

Correct option: B.
$1/\sqrt {2a} $
b
(b) $\mathop {\lim }\limits_{x \to a} \,\frac{{\sqrt {3x - a} - \sqrt {x + a} }}{{x - a}}$

$ = \mathop {\lim }\limits_{x \to a} \,\frac{{\sqrt {3x - a} - \sqrt {x + a} }}{{(x - a)}} \times \frac{{\sqrt {3x - a} + \sqrt {x + a} }}{{\sqrt {3x - a} + \sqrt {x + a} }}$

$ = \frac{2}{{2\sqrt {2a} }} = \frac{1}{{\sqrt {2a} }}$

Aliter : Apply $L$- Hospital’s rule

$\mathop {\lim }\limits_{x \to a} \,\frac{{\sqrt {3x - a} - \sqrt {x + a} }}{{x - a}} = \mathop {\lim }\limits_{x \to a} \,\frac{3}{{2\,\sqrt {3x - a} }} - \frac{1}{{2\,\sqrt {x + a} }}$

$ = \frac{3}{{2\sqrt {2a} }} - \frac{1}{{2\sqrt {2a} }} = \frac{1}{{\sqrt {2a} }}.$

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