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STD 11 - 12. limits — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 12. limits4 Marks
MCQ
$\mathop {\lim }\limits_{x \to \infty } \frac{{{{(2x + 1)}^{40}}{{(4x - 1)}^5}}}{{{{(2x + 3)}^{45}}}} = $
  • A
    $16$
  • B
    $24$
  • ✓
    $32$
  • D
    $8$
✓

Answer

Correct option: C.
$32$
c
(c) $\mathop {\lim }\limits_{x \to \infty } \frac{{{{(2 + \frac{1}{x})}^{^{40}}}{{(4 - \frac{1}{x})}^5}}}{{{{(2 + \frac{3}{x})}^{45}}}} = \frac{{{2^{40}}}}{{{2^{45}}}} = {2^5} = 32$

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