_ x 3 x^2 + 2x - 1 2 x^2 - 3x - 3 = - Vidyadip

MCQ

$\mathop {\lim }\limits_{x \to \infty } \frac{{3{x^2} + 2x - 1}}{{2{x^2} - 3x - 3}} = $

A
$1$
B
$3$
✓
$\frac{3}{2}$
D
$ - \frac{3}{2}$

✓

Answer

Correct option: C.

$\frac{3}{2}$

c
(c)$\mathop {\lim }\limits_{x \to \infty } \,\,\frac{{3 + (2/x) - (1/{x^2})}}{{2 - (3/x) - (3/{x^2})}} = \frac{3}{2}.$

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