Question
$\mathop {\lim }\limits_{x \to \infty } \frac{{(x - 1)(2x + 3)}}{{{x^2}}} = $

Answer

c
(c) $\mathop {\lim }\limits_{x \to \infty } \,\,\frac{{(x - 1)\,\,(2x + 3)}}{{{x^2}}} = \mathop {\lim }\limits_{x \to \infty } \,\,\frac{{2{x^2} + x - 3}}{{{x^2}}} = 2.$

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