MCQ
$\mathop {\lim }\limits_{x \to \pi /2} \frac{{1 + \cos 2x}}{{{{(\pi - 2x)}^2}}} = $
  • A
    $1$
  • B
    $2$
  • C
    $3$
  • $\frac{1}{2}$

Answer

Correct option: D.
$\frac{1}{2}$
d
(d) $\pi - 2x = \theta \,\, \Rightarrow \,\,x = \frac{\pi }{2} - \frac{\theta }{2}$

and as $x \to \,(\pi /2),\,\,\theta \to 0$

Now solve yourself.

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