MCQ
$\mathop {Limit}\limits_{x\,\, \to \,\,0} $ ${\left( {\cos \,2x} \right)^{3\,/\,{x^2}}}$ has the value equal to ______ .
  • A
    $e^{-3}$
  • B
    $e^{-4}$
  • C
    $e^{-5}$
  • $e^{-6}$

Answer

Correct option: D.
$e^{-6}$
d
The limit should be $\frac{1}{e^{6}}$ $\lim _{x \rightarrow 0} \cos \frac{3}{x^{2}}(2 x)=$

But:

$\cos ^{\frac{3}{x^{2}}}(2 x)=e^{\frac{3}{x^{2}} \ln |\cos (2 x)|}$ (have a look at the properties of logarithms)

and:

$\lim _{x \rightarrow 0} e^{\frac{3}{x^{2}} \ln [\cos (2 x) \mid}=e^{-6}$

The exponent $\frac{3}{x^{2}} \ln [\cos (2 x)]$ tends to -6

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $m$ rupee coins and $n$ ten paise coins are placed in a line, then the probability that the extreme coins are ten paise coins is
The integral $80 \int_{0}^{\frac{\pi}{4}}\left(\frac{\sin \theta+\cos \theta}{9+16 \sin 2 \theta}\right) d \theta$ is equal to :
The number of elements in the set $S=$ $\left\{\theta \in[-4 \pi, 4 \pi]: 3 \cos ^{2} 2 \theta+6 \cos 2 \theta-\right.$ $\left.10 \cos ^{2} \theta+5=0\right\}$ is
If $y = sin^{-1 }\left( {x\sqrt {1\,\, - \,\,x} \,\,\, + \,\,\,\sqrt x \,\,\sqrt {1\, - \,{x^2}} } \right) \&\,\, \frac{{dy}}{{dx}}= \frac{1}{{2\,\sqrt {x\,(1\,\, - \,\,x)} }}+ p$, then $p =$
A bag contains $6$ red, $4$ white and $8$ blue balls. If three balls are drawn at random, then the probability that $2$ are white and $1$ is red, is
If ${9 \over {(x - 1)\,{{(x + 2)}^2}}} = {A \over {x - 1}} + {B \over {x + 2}} + {C \over {{{(x + 2)}^2}}}$ then $A - B - C = $
The locus of the mid point of the line segment joining the point $(4,3)$ and the points on the ellipse $x^{2}+2 y^{2}=4$ is an ellipse with eccentricity
Let $\overrightarrow{P R}=3 \hat{i}+\hat{j}-2 \hat{k}$ and $\overrightarrow{S Q}=\hat{i}-3 \hat{j}-4 \hat{k}$ determine diagonals of a parallelogram $P Q R S$ and $\overrightarrow{P T}=\hat{i}+2 \hat{j}+3 \hat{k}$ be another vector. Then the volume of the parallelepiped determined by the vectors $\overrightarrow{ PT }, \overrightarrow{ PQ }$ and $\overrightarrow{ PS }$ is
The coordinates of the foot perpendicular from the point $( 1 , 0, 0)$ to the line $\frac{{x - 1}}{2} = \frac{{y + 1}}{{ - 3}} = \frac{{z + 10}}{8}$ are
Let $f(x) = \frac{x}{{1 + |x|}}$ be differentiable at  . . . .