MCQ
$\mathop {Limit}\limits_{x\,\, \to \,\,0} $ ${\left( {\cos \,2x} \right)^{3\,/\,{x^2}}}$ has the value equal to ______ .
  • A
    $e^{-3}$
  • B
    $e^{-4}$
  • C
    $e^{-5}$
  • $e^{-6}$

Answer

Correct option: D.
$e^{-6}$
d
The limit should be $\frac{1}{e^{6}}$ $\lim _{x \rightarrow 0} \cos \frac{3}{x^{2}}(2 x)=$

But:

$\cos ^{\frac{3}{x^{2}}}(2 x)=e^{\frac{3}{x^{2}} \ln |\cos (2 x)|}$ (have a look at the properties of logarithms)

and:

$\lim _{x \rightarrow 0} e^{\frac{3}{x^{2}} \ln [\cos (2 x) \mid}=e^{-6}$

The exponent $\frac{3}{x^{2}} \ln [\cos (2 x)]$ tends to -6

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free