MCQ
Maximum boiling point would be shown by:
- A$\ce{CH_3−O−CH_3}$
- B$\ce{C_2_5−O−C_2H_5}$
- ✓$\ce{CH_3−CH_2−CH_2−OH}$
- D$\ce{(CH_3)_2CH−OH}$
✓
Answer
Correct option: C.
$\ce{CH_3−CH_2−CH_2−OH}$
Maximum boiling point would be shown by n propanol$, \ce{CH_3−CH_2−CH_2−OH}$
In $n-$propanol, the molecules are associated due to hydrogen bonding. Hence, the boiling point is higher. In dimethyl ether and diethyl ether, the boiling point is lower as hydrogen bonding is not possible.
The extent of the hydrogen bonding in isopropanol is lower than that in $n-$propanol due to $+I$ effect of two methyl groups.Also, as the degree of branching increases, the boiling point decreases.
In $n-$propanol, the molecules are associated due to hydrogen bonding. Hence, the boiling point is higher. In dimethyl ether and diethyl ether, the boiling point is lower as hydrogen bonding is not possible.
The extent of the hydrogen bonding in isopropanol is lower than that in $n-$propanol due to $+I$ effect of two methyl groups.Also, as the degree of branching increases, the boiling point decreases.
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