Question
Median of the data may or may not be from the given data.
✓
Answer
$e.g.$
$i. 2, 4, 6, 8$
Here, $n = 5($odd$)$
Median $=$ Value of $\Big(\frac{\text{n+1}}{2}\Big)^\text{th}$ observation
$=$ Value of $\Big(\frac{5+1}{2}\Big)^\text{th}$ observation
$=$ Value of $3^{rd}$ observation $= 6$
$ii. 4, 6, 8, 8, 12, 14, 15, 16$
Here, $n = 8($even$)$
Median $=\frac{\text{Value of }\Big(\frac{\text{n}}{2}\Big)^\text{th }\text{observation = Value of}\Big(\frac{\text{n}}{2}+1\Big)^\text{th }\text{observation}}{2}$
$=\frac{\text{Value of $4^{th}$ observation + Value of $5^{th}$ observation}}{2}$
$=\frac{8+12}{2}$
$=\frac{20}{2}$
$=10$
$i. 2, 4, 6, 8$
Here, $n = 5($odd$)$
Median $=$ Value of $\Big(\frac{\text{n+1}}{2}\Big)^\text{th}$ observation
$=$ Value of $\Big(\frac{5+1}{2}\Big)^\text{th}$ observation
$=$ Value of $3^{rd}$ observation $= 6$
$ii. 4, 6, 8, 8, 12, 14, 15, 16$
Here, $n = 8($even$)$
Median $=\frac{\text{Value of }\Big(\frac{\text{n}}{2}\Big)^\text{th }\text{observation = Value of}\Big(\frac{\text{n}}{2}+1\Big)^\text{th }\text{observation}}{2}$
$=\frac{\text{Value of $4^{th}$ observation + Value of $5^{th}$ observation}}{2}$
$=\frac{8+12}{2}$
$=\frac{20}{2}$
$=10$
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