MCQ
Mercury is a liquid at $0\,^o C$ because of
- Avery high ionisation energy
- Bweak metallic bonds
- Chigh heat of hydration
- ✓Both $(a)$ and $(b)$
✓
Answer
Correct option: D.
Both $(a)$ and $(b)$
d
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Using the given figure, the ratio of $R_t$ values of sample $A$ and sample $\mathrm{C}$ is $\mathrm{x} \times 10^{-2}$. Value of $\mathrm{x}$ is . . . . . . . .
→(Image)
Samples $(A, B, C)$
Fig : Paper chromatography of Samples
Consider the following statements :
→$(a)$ Electron density in the $XY$ plane in $3d_x^2 - 3d_y^2$ orbital is zero
$(b)$ Electron density in the $XY$ plane in $3d_z^2$ orbital is zero
$(c)$ $2s$ orbital has one nodal surface
$(d)$ For $2pz$ orbital $YZ$ is the nodal plane.
Specify True or False.
Oxidation state of both the chlorine atoms in bleaching powder are ?
The relation between equilibrium constant ${K_p}$ and ${K_c}$ is
→$3.2$ moles of hydrogen iodide were heated in a scaled bulb at $444\,^oC$ till the equilibrium was reached. The degree of dissociation of $HI$ at this temperature was found to be $22\%$. The number of moles of hydrogen iodide present at equilibrium are
→${H_3}C - C \equiv CH\,\xrightarrow{{NaN{H_2}}}A\,\xrightarrow{{C{H_3}C{H_2}Br}}B\xrightarrow[{BaS{O_4}}]{{{H_2}/Pd}}C$
→Identify product $(C)$ ?
It is found that for every $10^o$ rise in temperature, the rate of the reaction doubles itself. This is mainly because
→Which blue liquid is obtained on reacting equimolar amounts of two gases at $ - 30\,^oC$
→A hypothetical electromagnetic wave is show below.
→(Image)
The frequency of the wave is $\mathrm{x} \times 10^{19} \mathrm{~Hz}$. $x=$ . . . . (nearest integer)
The ionisation energy of nitrogen is more than that of oxygen because :-