- A$Zn$
- B$Cu$
- C$Ag$
- ✓$Cd$
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A current was passed for $10$ hours. $10.8\ g Ag$ was deposited at cathode in $(III)$ electrolytic cell during electrolysis if current efficiency is $50\%.$
If $Z_1,$ $Z_2$ and $Z_3$ be the electrochemical equivalent in the formation of $H_2, Cu$ and $Ag$ respectively, hence $Z_1 : Z_2 : Z_3$ would be
$C{H_3}C{H_2}I + KO{H_{(aq)}} \to C{H_3}C{H_2}OH + KI$
is classified as :
$(i)\, EMF$ of cell = (Oxidation potential of anode) $-$ (Reduction potential of cathode)
$(ii)\,EMF$ of cell = (Oxidation potential of anode) $+$ (Reduction potential of cathode)
$(iii)\,EMF$ of cell = (Reductional potential of anode) $+$ (Reduction potential of cathode)
$(iv)\,EMF$ of cell = (Oxidation potential of anode) $-$ (Oxidation potential of cathode)
Which of the above relations are correct?
