MCQ
Metallic solids are always opaque because
- ASolids effect the incident light
- ✓Incident light is readily absorbed by the free electron in a metal
- CIncident light is scattered by solid molecules
- DEnergy band traps the incident light
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$[A]$ After a long time, the current through $L_1$ will be $\frac{V}{R} \frac{L_2}{~L_1+L_2}$
$[B]$ After a long time, the current through $\mathrm{L}_2$ will be $\frac{\mathrm{V}}{\mathrm{R}} \frac{\mathrm{L}_1}{\mathrm{~L}_1+\mathrm{L}_2}$
$[C]$ The ratio of the currents through $L_1$ and $L_2$ is fixed at all times $(t>0)$
$[D]$ At $t=0$, the current through the resistance $R$ is $\frac{V}{R}$

