- ACovalent character
- ✓Hydrogen bonding character
- COxygen bonding character
- DNone of these
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$M(s) + \frac{1}{2}{O_2}(s)\, \to \,MO(s)\,$ and $C(s) + \frac{1}{2}{O_2}(g)\, \to \,CO(s)\,$
Identify the correct statement
$I ^{-}+ ClO _3^{-}+ H _2 SO _4 \longrightarrow Cl ^{-}+ HSO _4^{-}+ I _2$
The correct statement(s) in the balanced equation is/are:
$(A)$ Stoichiometric coefficient of $HSO _4^{-}$is 6 .
$(B)$ lodide is oxidized.
$(C)$ Sulphur is reduced.
$(D)$ $H _2 O$ is one of the products.
$\begin{array}{*{20}{c}}
{C{H_3} - C = CH - C{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{CH{{(C{H_3})}_2}\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow[{(ii)\,{H_2}{O_2},O{H^ - }}]{{(i)\,{B_2}{H_6}}}[A]$$\xrightarrow[\Delta ]{{dil.\,{H_2}S{O_4}}}[B]$
$(a)\ Pb^{+2} > Pb^{+4} , Tl^{+1} < Tl^{+3}$
$(b)\ Bi^{+3} < Sb^{+3 }, Sn^{+2} < Sn^{+4}$
$(c)\ Pb^{+2} > Pb^{+4} , Bi^{+3} > Bi^{+5}$
$(d)\ Tl^{+3} < In^{+3} , Sn^{+2} > Sn^{+4}$
$(e)\ Sn^{+24} < Pb^{+2} , Sn^{+4} > Pb^{+4}$
$(f)\ Sn^{+2} < Pb^{+2} , Sn^{+4} < Pb^{+4}$