- AIt stops respiratory track
- ✓It reacts with nitrogen and forms $C{N^ - }$ in the lungs
- CIt increases $C{O_2}$ content in the blood
- DIt is a reduction product of formaldehyde
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| $[HI]$, $M$ | rate, $Ms^{-1}$ |
| $0.0500$ | $8.80 \times {10^{ - 10}}$ |
| $0.1000$ | $3.52 \times {10^{ - 9}}$ |
| $0.1500$ | $7.92 \times {10^{ - 9}}$ |
$Q (47 \%)$ and $R (2 \%)$. The major product(s) of the following reaction sequence is (are)
$\begin{array}{l}\begin{array}{ll}\text { 1) } Ac _2 O \text {, pyridine } \quad \text { 1) } Sn / HCl \end{array} \\ R \xrightarrow{2) Br _2, CH _3 CO _2 H } S \quad \xrightarrow{2) Br _2 / H _2 O \text { (excess) }} \text { major product(s) } \\ \text { 3) } H _3 O ^{+} \quad \text {3) } NaNO _2, HCl / 273-278 K \\ \text { 4) } NaNO _2, HCl / 273-278 K \quad \text { 4) } H _3 PO _2 \\ \text { 5) } EtOH , \Delta \\\end{array}$
$2NO(g) + 2{H_2}(g) \to {N_2}(g) + 2{H_2}O(g)$ is :
Step $1$ : $2NO(g) + {H_2}(g)\xrightarrow{{slow}}{N_2} + {H_2}{O_2}$
Step : $2$ ${H_2}{O_2} + {H_2}\xrightarrow{{fast}}2{H_2}O$
Then the correct statement is
