- A$2\sqrt 2$
- ✓$2\sqrt 2 - 1$
- C$2 + 3\sqrt 2 $
- D$2\sqrt 2 + 1$
$\sin x \cos x=\left(\frac{p^{2}-1}{2}\right)$
$\therefore f(x) = \left| {p + \frac{2}{{\left( {{p^2} - 1} \right)}} + \frac{{2p}}{{{p^2} - 1}}} \right|$
${=\left|p+\frac{2}{(p-1)}\right|} $
${=\left|(p-1)+\frac{2}{(p-1)}+1\right|}$
$\therefore \frac{(p-1)+\left(\frac{2}{p-1}\right)}{2} \geq\left((p-1) \cdot \frac{2}{p-1}\right)^{1 / 2}$
$\therefore(p-1)+\left(\frac{2}{p-1}\right) \geq 2 \sqrt{2}$
$\therefore \quad f(x)_{\min } \geq 2 \sqrt{2}+1$
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$(A)$ $\left|z+\frac{1}{2}\right| \leq \frac{1}{2}$ for all $z \in S$ $(B)$ $|z| \leq 2$ for all $z \in S$
$(C)$ $\left|z+\frac{1}{2}\right| \geq \frac{1}{2}$ for all $z \in S$ $(D)$ The set $S$ has exactly four elements
$a x+2 y=\lambda$
$3 x-2 y=\mu$Which of the following statement($s$) is(are) correct?
($A$) If $a=-3$, then the system has infinitely many solutions for all values of $\lambda$ and $\mu$
($B$) If $a \neq-3$, then the system has a unique solution for all values of $\lambda$ and $\mu$
($C$) If $\lambda+\mu=0$, then the system has infinitely many solutions for $a=-3$
($D$) If $\lambda+\mu \neq 0$, then the system has no solution for $a=-3$
